Answer
-2.4456
Work Step by Step
Based on the change of base property for common logarithms, we know that $log_{b}M=\frac{log(M)}{log(b)}$.
Therefore, $log_{.3}19=\frac{log(19)}{log(.3)}=\frac{1.2788}{-0.5229}\approx-2.4456$.
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.3 - Page 477: 76
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