Answer
$=\log(\frac{x(x-1)}{7})$
Work Step by Step
$= \log x + \log (x^{2}-1) - \log 7 - \log (x+1)$
$= \log(x(x^{2}-1)) - \log 7 - \log (x+1)$
$= \log(\frac{x(x^{2}-1)}{7}-\log(x+1))$
$=\log (\frac{x(x^{2}-1)}{7(x+1)})$
$=\log (\frac{x(x+1)(x-1)}{7(x+1)})$
$=\log(\frac{x(x-1)}{7})$