College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.3 - Page 477: 75



Work Step by Step

Based on the change of base property for common logarithms, we know that $log_{b}M=\frac{log(M)}{log(b)}$. Therefore, $log_{.1}17=\frac{log(17)}{log(.1)}=\frac{1.2304}{-1}\approx-1.2304$.
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