Chapter 3 - Polynomial and Rational Functions - Exercise Set 3.1 - Page 343: 8

$j(x)=-x^{2}-1$

$f(x)=x^{2}+2x+1$ $g(x)=x^{2}-2x+1$ $h(x)=x^{2}-1$ $j(x)=-x^{2}-1$ First, you will notice that the graph has a y-intercept of $-1$ and that it opens downwards. Therefore, $j(x)=-x^{2}-1$ is the correct answer.