Answer
The axis of symmetry is $x=3$.
domain: $(-\infty,\infty)$
range: $[1, \infty)$
Work Step by Step
To graph $f(x)=a(x-h)^{2}+k$,
1. Determine whether the parabola opens upward or downward.
If $a>0$, it opens upward. If $a<0$, it opens downward.
2. Determine the vertex of the parabola. The vertex is $(h, k)$.
3. Find any x-intercepts by solving $f(x)=0$.
The function's real zeros are the x-intercepts.
4. Find the y-intercept by computing $f(0)$.
5. Plot the intercepts, the vertex, and additional points as necessary
Connect these points with a smooth curve that is shaped like a bowl or an inverted bowl.
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$y-1=(x-3)^{2}\qquad.../+1$
$y=(x-3)^{2}+1$
1. opens up (a=1).
2. vertex: (3, 1)$. $The axis of symmetry is $x=$1.
x-intercepts:
$0=(x-3)^{2}+1$
$(x-3)^{2}=-1$
(a square of a real number can not be $-1$)
No x-intercepts.
y-intercept:
$y=(0-3)^{2}+1=10$
5. see graph
The axis of symmetry is $x=3$.
domain: $(-\infty,\infty)$
range: $[1, \infty)$
