## College Algebra (6th Edition)

$f(x)=x^{2}+2x+1$
$f(x)=x^{2}+2x+1$ $g(x)=x^{2}-2x+1$ $h(x)=x^{2}-1$ $j(x)=-x^{2}-1$ First, you will notice that the graph has an axis of symmetry of $x=-1$ and that it opens upwards. Also, when plugging in the values to the equation $\frac{-b}{2a}$, you would also get $-1$. Therefore, $f(x)=x^{2}+2x+1$ is the correct answer.