Answer
$h(x)=x^{2}-1$
Work Step by Step
$f(x)=x^{2}+2x+1$
$g(x)=x^{2}-2x+1$
$h(x)=x^{2}-1$
$j(x)=-x^{2}-1$
First, you will notice that the graph has a y-intercept of $1$ and that it opens upwards. Therefore, $h(x)=x^{2}-1$ is the correct answer.