#### Answer

$j(x)=(x-1)^{2}-1$

#### Work Step by Step

$f(x)=(x+1)^{2}-1$
$g(x)=(x+1)^{2}+1$
$h(x)=(x-1)^{2}+1$
$j(x)=(x-1)^{2}-1$
First, you will notice the graph has the vertex $(1,-1)$. The $-1$ inside the parentheses of $j(x)$ moves to the right one unit and the outside number moves down one unit. Therefore, $j(x)=(x-1)^{2}-1$ is the correct answer.