College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 3 - Polynomial and Rational Functions - Exercise Set 3.1 - Page 343: 3

Answer

$j(x)=(x-1)^{2}-1$

Work Step by Step

$f(x)=(x+1)^{2}-1$ $g(x)=(x+1)^{2}+1$ $h(x)=(x-1)^{2}+1$ $j(x)=(x-1)^{2}-1$ First, you will notice the graph has the vertex $(1,-1)$. The $-1$ inside the parentheses of $j(x)$ moves to the right one unit and the outside number moves down one unit. Therefore, $j(x)=(x-1)^{2}-1$ is the correct answer.
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