College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.7 - Page 196: 95


$(-∞, -3]$

Work Step by Step

Plug the given conditions into an inequality. Put similar terms on either side and then find the least common denominator of all the terms to eliminate the fractions. Then simplify by isolating $x$. $\frac{x}{2}+3\leq\frac{x}{3}+\frac{5}{2}$ $\frac{x}{2}+\frac{1}{2}\leq\frac{x}{3}$ $6(\frac{x}{2}+\frac{1}{2})\leq6(\frac{x}{3})$ $3x+3\leq2x$ $-3\geq x$ $x\leq-3$ $(-∞, -3]$
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