College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.7 - Page 196: 67


$-6\lt x\lt0$

Work Step by Step

The absolute value will keep the sign the same and the other side positive, and it will also flip the sign and make the other side negative. Solve for each inequality by multiplying both sides, subtracting from both sides, and dividing. $|\frac{2x+6}{3}|\lt2$ $\frac{2x+6}{3}\lt2$ $2x+6\lt6$ $2x\lt0$ $x\lt0$ $\frac{2x+6}{3}\gt-2$ $2x+6\gt-6$ $2x\gt-12$ $x\gt-6$ $-6\lt x\lt0$
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