## College Algebra (6th Edition)

$x\lt\frac{1}{3},x\gt5$
Solve for the original inequality, and then flip the sign and make the opposite side negative in the second inequality. $3x-8\gt7$ $3x\gt15$ $x\gt5$ $3x-8\lt-7$ $3x\lt1$ $x\lt\frac{1}{3}$ $x\lt\frac{1}{3},x\gt5$