Answer
$\emptyset$
Work Step by Step
$ 5(x-2)-3(x+4)\geq 2x-20 \qquad$ ... distribute
$ 5x-10-3x-12\geq 2x-20 \qquad$ ... simplify
$ 2x-22\geq 2x-20 \qquad$ ... add $22-2x $ to both sides
$0\geq-2$
This is not true for any real $x$.
The solution set is the empty set, $\emptyset$.
