## College Algebra (6th Edition)

$(-∞ ,-\frac{53}{6}]$
Subtract $45$ and $12x$ on both sides. Then divide to get $x$. $18x+45\leq12x-8$ $6x\leq-53$ $x\leq-\frac{53}{6}$ $(-∞ ,-\frac{53}{6}]$