#### Answer

$\emptyset$

#### Work Step by Step

$ 6(x-1)-(4-x)\geq 7x-8 \qquad$ ... distribute
$ 6x-6-4+x\geq 7x-8 \qquad$ ... simplify
$ 7x-10\geq 7x-8\qquad$ ... add $10-7x $ to both sides
$0\geq 2$
This is not true for any real $x$.
The solution set is the empty set, $\emptyset$.