## College Algebra (6th Edition)

$[13,\infty)$
$\displaystyle \frac{x-4}{6}\geq\frac{x-2}{9}+\frac{5}{18}\qquad$ ... multiply both sides with the LCD, 18 $3(x-4)\geq 2(x-2)+5\qquad$ ... distribute $3x-12\geq 2x-4+5\qquad$ ... add $12-2x$ to both sides $x\geq 13$ Solution set : $[13,+\infty)$