College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.7 - Page 196: 46


$[-\displaystyle \frac{19}{6},\infty)$

Work Step by Step

$\displaystyle \frac{4x-3}{6}+2\geq\frac{2x-1}{12}\qquad$ ... multiply both sides with the LCD, $12$ $ 2(4x-3)+24\geq 2x-1\qquad$ ... distribute $ 8x-6+24\geq 2x-1\qquad$ ... add $18-2x $ to both sides $6x\geq-19\qquad$ ... divide both sides with 6 $x\displaystyle \geq-\frac{19}{6}$ Solution set : $[-\displaystyle \frac{19}{6},+\infty)$
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