## College Algebra (6th Edition)

$[-\displaystyle \frac{19}{6},\infty)$
$\displaystyle \frac{4x-3}{6}+2\geq\frac{2x-1}{12}\qquad$ ... multiply both sides with the LCD, $12$ $2(4x-3)+24\geq 2x-1\qquad$ ... distribute $8x-6+24\geq 2x-1\qquad$ ... add $18-2x$ to both sides $6x\geq-19\qquad$ ... divide both sides with 6 $x\displaystyle \geq-\frac{19}{6}$ Solution set : $[-\displaystyle \frac{19}{6},+\infty)$