College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 6 - Section 6.1 - Parabolas - 6.1 Exercises - Page 590: 37

Answer

$x^2=y$

Work Step by Step

Since the parabola is opening up, it means that the parabola is vertical. The standard form of a vertical parabola is given as: $x^2=4py ~~~(1)$ (when the parabola has the vertex at origin $(0,0)$) Here, the point $(\sqrt 3, 3)$ is on the graph, so we have: $x=\sqrt 3; y=3$ Now, we will plug the values of $x$ and $y$ in the standard form of parabola to calculate $p$: $(\sqrt 3)^2=4p \times (3)$ or, $12 p=3 \implies p=\frac{1}{4}$ Thus, the equation (1) becomes: $x^2 =(4)\left(\frac{1}{4}\right) y \implies x^2=y$
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