College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 6 - Section 6.1 - Parabolas - 6.1 Exercises - Page 590: 34

Answer

$y^2=-2 x$

Work Step by Step

We are given that vertex is at origin, that is, $(0,0)$ and focus is at $\left(-\frac{1}{2},0\right)$. The fact that the focus is $(p,0)=\left(-\frac{1}{2},0\right)$ implies that the parabola is horizontal and $p-=\frac{1}{2}$. The general form of a horizontal parabola is $y^2=4px$ when the vertex is at origin. Thus, the general form of a horizontal parabola becomes: $$y^2=(4)\left(-\dfrac{1}{2}\right )x \\ \implies y^2=-2 x$$
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