Answer
Focus = $(7,-1)$;
Directrix $y=-9$;
Axis of symmetry $x=7$
Work Step by Step
The given equation can be re-written as:
$(x-7)^2 = 4p[y-(-5)]$
Here, $4p=16 \implies p=4$ and vertex $(h,k)=(7,-5)$
Since the parabola is vertical as $x$ is squared, the axis of symmetry is $x=7$.
with focus $(h,k+p)=(7,-5+4)=(7,-1)$.
Now, the directrix is $y=k-p=-5-4=-9$.
Our results are:
Focus = $(7,-1)$;
Directrix $y=-9$;
Axis of symmetry $x=7$.
