Answer
Vertex =$(0,0)$;
Focus $=(0,6)$;
Directrix $y=-6$;
Axis of symmetry $x=0$
Work Step by Step
We are given that $x^2=24y$
This equation has the form as $x^2 =4py$ wherein $4p=24 \implies p=6$.
Here, the vertex is $(0,0)$ and the axis of symmetry is the $y$-axis, that is, $x=0$
and the $x$-term is squared which shows that the parabola is vertical with focus $(0,p)=(0,6)$.
Now, the directrix is $y=-p=-6$
Our results are:
Vertex =$(0,0)$;
Focus $=(0,6)$;
Directrix $y=-6$;
Axis of symmetry $x=0$
