College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 6 - Section 6.1 - Parabolas - 6.1 Exercises - Page 590: 25

Answer

Focus = $(-1, 0)$; Directrix $x=1$; Axis of Symmetry $y=0$

Work Step by Step

The equation is in the form $y^2=4px$. Here, $4p=-4 \implies p=-1$ and vertex $(h,k)=(0,0)$ Since, the parabola is horizontal, the axis of symmetry is $y=0$ with focus $(p,0)=(-1, 0)$ Now, the directrix is $x=-p=-(-1)=1$ Our results are: Focus $=(-1, 0)$; Directrix $x=1$; Axis of symmetry $y=0$.
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