College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 6 - Section 6.1 - Parabolas - 6.1 Exercises - Page 590: 30

Answer

Focus = $(9,2)$; Directrix $x=-3$; Axis of symmetry $y=2$

Work Step by Step

The given parabola has general form $(y-k)^2=4p(x-h)$ Here, $4p=24 \implies p=6$ and vertex $(h,k)=(3, 2)$. Since, the parabola is horizontal, the axis of symmetry is $y=k=2$ with focus $(h+p, k)=(3+6,2)=(9,2)$ Now, the directrix is $x=h-p=3-6=-3$ Our results are: Focus = $(9,2)$; Directrix $x=-3$; Axis of symmetry $y=2$.
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