Answer
Focus = $(4,3)$;
Directrix $x=-2$;
Axis of symmetry $y=3$
Work Step by Step
The given parabola has general form $(y-k)^2=4p(x-h)$
Here, $4p=12 \implies p=3$ and vertex $(h,k)=(1, 3)$
Since, the parabola is horizontal, the axis of symmetry is $y=k=3$
with focus $(h+p, k)=(1+3,3)=(4,3)$
Now, the directrix is $x=h-p=1-3=-2$
Our results are:
Focus = $(4,3)$;
Directrix $x=-2$;
Axis of symmetry $y=3$.
