College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 6 - Section 6.1 - Parabolas - 6.1 Exercises - Page 590: 32

Answer

Focus = $(-2, 7)$; Directrix $y=-3$; Axis of symmetry $x=-2$

Work Step by Step

The given equation can be re-written as: $(x-(-2))^2 = 4p(y-2)$ Here, $4p=20 \implies p= 5$ and vertex $(h,k)=(-2, 2)$ Since the parabola is vertical as $x$ is squared, the axis of symmetry is $x=-2$ with focus $(h,k+p)=(-2, 2+5)=(-2,7)$. Now, the directrix is $y=k-p=2-5=-3$. Our results are: Focus = $(-2, 7)$; Directrix $y=-3$; Axis of symmetry $x=-2$.
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