Answer
Focus = $(4, 0)$;
Directrix $x=-4$;
Axis of symmetry $y=0$
Work Step by Step
The equation is in the form $y^2=4py$. Here, $4p=16 \implies p=4$ and vertex $(h,k)=(0,0)$
Since, the parabola is horizontal, the axis of symmetry is $y=0$
with focus $(p,0)=(4, 0)$
Now, the directrix is $x=-p=-4$
Our results are:
Focus = $(4, 0)$;
Directrix $x=-4$;
Axis of symmetry $y=0$
