Answer
$\dfrac{15}{8}$
Work Step by Step
Perform multiplication first to obtain:
$\require{cancel}
=\dfrac{2(3)}{4}+\dfrac{3}{8}
\\=\dfrac{6}{4}+\dfrac{3}{8}$
Simplify the first fraction by canceling the common factor $2$ to obtain:
$\require{cancel}
=\dfrac{\cancel{6}3}{\cancel{4}2} + \dfrac{3}{8}
\\=\dfrac{3}{2}+\dfrac{3}{8}$
Make the fractions similar using their LCD of $8$ to obtain:
$=\dfrac{3(4)}{2(4)}+\dfrac{3}{8}
\\=\dfrac{12}{8} + \dfrac{3}{8}
\\=\dfrac{12+3}{8}
\\=\dfrac{15}{8}$
