## College Algebra (10th Edition)

$\dfrac{4}{5}$
Multiply the fractions first to obtain: $\require{cancel} =\dfrac{2}{3}+\dfrac{4(1)}{5(6)} \\=\dfrac{2}{3}+\dfrac{4}{30} \\=\dfrac{2}{3} + \dfrac{\cancel{4}2}{\cancel{30}15} \\=\dfrac{2}{3}+\dfrac{2}{15}$ Make the fractions similar using their LCD of $15$ to obtain: $=\dfrac{2(5)}{3(5)}+\dfrac{2}{15} \\=\dfrac{10}{15} + \dfrac{2}{15} \\=\dfrac{10+2}{15} \\=\dfrac{12}{15}$ Cancel the common factor $3$ to obtain: $\require{cancel} =\dfrac{\cancel{12}4}{\cancel{15}5} \\=\dfrac{4}{5}$