College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.1 - Real Numbers - R.1 Assess Your Understanding - Page 16: 80

Answer

$\dfrac{5}{42}$

Work Step by Step

Find the LCM (lease common multiple) of the denominators: $14 = 7(2) \\21=7(3)$ The LCM is $7(2)(3) = 42$ Thus, the LCD is also $42$ Make the fractions similar using their LCD to obtain: $=\dfrac{3(3)}{14(3)} - \dfrac{2(2)}{21(2)} \\=\dfrac{9}{42}-\dfrac{4}{42} \\=\dfrac{9-4}{42} \\=\dfrac{5}{42}$
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