## College Algebra (10th Edition)

$\dfrac{46}{45}$
Find the LCD of the two fractions: $15 = 5(3) \\9=3(3)$ The LCM is $5(3)(3) =45$ Thus, the LCD is also $45$ Make the fractions similar using their LCD to obtain: $=\dfrac{2(3)}{15(3)} + \dfrac{8(5)}{9(5)} \\=\dfrac{6}{45}+\dfrac{40}{45} \\=\dfrac{6+40}{45} \\=\dfrac{46}{45}$