College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.1 - Real Numbers - R.1 Assess Your Understanding - Page 16: 77



Work Step by Step

Find the LCD of the two fractions: $18 = 6(3) \\12=6(2)$ Thus, the LCD is $6(3)(2) = 36$ Make the fractions similar using their LCD to obtain: $=\dfrac{5(2)}{18(2)} + \dfrac{1(3)}{12(3)} \\=\dfrac{10}{36}+\dfrac{3}{36} \\=\dfrac{10+3}{36} \\=\dfrac{13}{36}$
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