College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.1 - Real Numbers - R.1 Assess Your Understanding - Page 16: 71

Answer

$\dfrac{4}{45}$

Work Step by Step

Before multiplying the fractions, cancel common factors first to obtain: $\require{cancel} =\dfrac{\cancel{6}^2}{\cancel{25}^5} \cdot \dfrac{\cancel{10}^2}{\cancel{27}^9} \\=\dfrac{2(2)}{5(9)} \\=\dfrac{4}{45}$
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