## College Algebra (10th Edition)

$\dfrac{15}{22}$
RECALL: (1) $\dfrac{\frac{a}{b}}{\frac{c}{d}}=\dfrac{a}{b} \div \dfrac{c}{d}$ (2) $\dfrac{a}{b} \div \dfrac{c}{d} = \dfrac{a}{b}\cdot \dfrac{d}{c}$ Use the rules above to obtain: $\dfrac{5}{18} \div \dfrac{11}{27} \\=\dfrac{5}{18} \cdot \dfrac{27}{11}$ Cancel the common factor, $9$, and then simplify to obtain: $\require{cancel} =\dfrac{5}{\cancel{18}2} \cdot \dfrac{\cancel{27}3}{11} \\=\dfrac{5}{2} \cdot \dfrac{3}{11} \\=\dfrac{5(3)}{2(11)} \\=\dfrac{15}{22}$