College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.1 - Real Numbers - R.1 Assess Your Understanding - Page 16: 74

Answer

$\dfrac{11}{6}$

Work Step by Step

Make the fractions similar using their LCD of 6 to obtain: $=\dfrac{4(2)}{3(2)} + \dfrac{1(3)}{2(3)} \\=\dfrac{8}{6}+\dfrac{3}{6} \\=\dfrac{8+3}{6} \\=\dfrac{11}{6}$
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