College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.1 - Real Numbers - R.1 Assess Your Understanding - Page 16: 81

Answer

$\dfrac{1}{60}$

Work Step by Step

Find the LCM (lease common multiple) of the denominators: $20 = 5(2)(2) \\15=5(3)$ The LCM is $5(3)(2)(2) = 60$ Thus, the LCD is also $60$. Make the fractions similar using their LCD to obtain: $=\dfrac{3(3)}{20(3)} - \dfrac{2(4)}{15(4)} \\=\dfrac{9}{60}-\dfrac{8}{60} \\=\dfrac{9-8}{60} \\=\dfrac{1}{60}$
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