Answer
$x\gt-1$
Work Step by Step
We simplify as follows:
$0\lt(3x+6)^{-1}\lt\frac{1}{3}$
$0\lt\frac{1}{3x+6}\lt\frac{1}{3}$
$0\lt\frac{1}{3(x+2)}\lt\frac{x+2}{3(x+2)}$
$0\lt1\lt x+2$
$1\lt x+2$
$x\gt-1$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 1 - Section 1.5 - Solving Inequalities - 1.5 Assess Your Understanding - Page 128: 92
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