College Algebra (10th Edition)

$[\frac{4}{3},\infty)$
We solve the inequality: $\displaystyle \frac{x}{2}\geq 1-\frac{x}{4}$ $2x\geq 4*1-x$ $3x\geq 4$ $x\displaystyle \geq\frac{4}{3}$ Thus, the solution is the interval: $[\frac{4}{3},\infty)$