College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.5 - Solving Inequalities - 1.5 Assess Your Understanding - Page 128: 80

Answer

$\left\{x\ |\ x \lt -11 \right\}$ or $\left(-\infty,-11\right)$
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Work Step by Step

$(x-1)(x+1) \gt (x-3)(x+4)$ $x^{2}-1 \gt x^{2}+x-12 \qquad$ ... add $1-x-x^{2}$ $-x \gt -11\qquad$ ... multiply with $-1 $ (negative) ... the inequality changes direction ... $x \lt -11$ Solution set: $\left\{x\ | x \lt -11 \right\}$ or $\left(-\infty,-11\right)$
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