## College Algebra (10th Edition)

$\left\{x\ |\ -6 \lt x \lt 0 \right\}$ or $\left(-6,0\right)$
$1 \lt 1-\displaystyle \frac{1}{2}x \lt 4 \qquad$ ... add $-1$ $0 \lt -\displaystyle \frac{1}{2}x \lt 3 \qquad$ ... multiply with $-2$ (negative) ... the inequalities change direction ... $0 \gt x \gt -6$ or $-6 \lt x \lt 0$ Solution set: $\left\{x\ |\ -6 \lt x \lt 0 \right\}$ or $\left(-6,0\right)$