## College Algebra (10th Edition)

$$[12, \infty)$$
Solve the inequality as follows: $\frac{x}{3}\ge 2+\frac{x}{6}$ $\frac{x}{3}-\frac{x}{6}\ge 2$ $\frac{2x}{6}-\frac{x}{6}\ge 2$ $\frac{x}{6}\ge 2$ $x\ge 12$ Therefore, the solution in interval notation is $[12, \infty)$. The solution can be graphed as follows: