College Algebra (10th Edition)

$\displaystyle \left\{x\ |\ -\frac{2}{3} \lt x \lt 2 \right\}$ or $\displaystyle \left(-\frac{2}{3},2\right)$
$0 \lt \displaystyle \frac{3x+2}{2} \lt 4 \qquad$ ... multiply with $2$ $0 \lt 3x+2 \lt 8 \qquad$ ... add $-2$ $-2 \lt 3x \lt 6$... divide with $3$ $-\displaystyle \frac{2}{3} \lt x \lt 2$ Solution set: $\displaystyle \left\{x\ |\ -\frac{2}{3} \lt x \lt 2 \right\}$ or $\displaystyle \left(-\frac{2}{3},2\right)$