Answer
$(-\infty, \displaystyle \frac{2}{3}]$
Work Step by Step
We solve the inequality:
$4-3(1-x)\leq 3$
$4-3+3x\leq 3$
$1+3x\leq 3$
$3x\leq 2$
$x\leq\frac{2}{3}$
Thus, the solution is the interval: $(-\infty, \displaystyle \frac{2}{3}]$