Answer
$x\gt3$
Work Step by Step
We simplify as follows:
$0\lt(2x-4)^{-1}\lt\frac{1}{2}$
$0\lt\frac{1}{2x-4}\lt\frac{1}{2}$
$0\lt\frac{1}{2(x-2)}\lt\frac{x-2}{2(x-2)}$
$0\lt1\lt x-2$
$1\lt x-2$
$x\gt3$
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