College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.5 - Solving Inequalities - 1.5 Assess Your Understanding - Page 128: 91

Answer

$x\gt3$

Work Step by Step

We simplify as follows: $0\lt(2x-4)^{-1}\lt\frac{1}{2}$ $0\lt\frac{1}{2x-4}\lt\frac{1}{2}$ $0\lt\frac{1}{2(x-2)}\lt\frac{x-2}{2(x-2)}$ $0\lt1\lt x-2$ $1\lt x-2$ $x\gt3$
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