College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.5 - Solving Inequalities - 1.5 Assess Your Understanding - Page 128: 101


$a=4$ and $b=16$

Work Step by Step

We are given: $6\lt 3x\lt 12$ We divide by $3$: $\frac{6}{3}\lt \frac{3x}{3}\lt \frac{12}{3}$ $2\lt x\lt 4$ We take the square: $2^{2}\lt x^{2}\lt 4^{2}$ $4\lt x^{2}\lt 16$ Therefore: $a=4$ and $b=16$
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