Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 8 - 8.3 - Vectors in the Plane - 8.3 Exercises - Page 586: 69


$\lt \dfrac{9}{5},\dfrac{12}{5} \gt$

Work Step by Step

We are given that $||\overrightarrow{v}|| = 3$. So, $ \cos \theta =\dfrac{3}{5}; \sin \theta =\dfrac{4}{5}$ We know that $v=||v|| \lt \cos \theta , \sin \theta \gt $ Thus, $v=3 \lt \dfrac{3}{5},\dfrac{4}{5} \gt \\= \lt (3) (\dfrac{3}{5}),(3) (\dfrac{4}{5} ) \gt \\= \lt \dfrac{9}{5},\dfrac{12}{5} \gt$
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