Algebra and Trigonometry 10th Edition

Published by Cengage Learning

Chapter 8 - 8.3 - Vectors in the Plane - 8.3 Exercises - Page 586: 61

Answer

Magnitude: $6\sqrt 2$ Direction Angle: $315^{o}$

Work Step by Step

$\overrightarrow{v} = 6\widehat{i} - 6\widehat{j}$ Magnitude: $||\overrightarrow{v}|| = \sqrt {6^{2} + 6^{2}} = \sqrt 72 = 6\sqrt 2$ Direction Angle: $tan\theta = \frac{-6}{6} = -1$ $\theta = -45^{o}$ The angle is equivalent to: $315^{o}$

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