## Algebra and Trigonometry 10th Edition

Published by Cengage Learning

# Chapter 8 - 8.3 - Vectors in the Plane - 8.3 Exercises - Page 586: 47

#### Answer

$\lt -6, 8 \gt$

#### Work Step by Step

Since $v$ has the same direction as $u$ and since it is a multiple of a unit vector $n$, we can write it as: $\overrightarrow{v} = < -3 n, 4n>$ To find the unit vector, we must first find the magnitude: $\sqrt {((-3n)^{2} + (4n)^{2}} = 10$ or, $9n^2+16n^2 =100$ This implies that $n^2=4 \implies n=2$ Now, $\overrightarrow{v} = < -3 (2), 4 (2)> = \lt -6, 8 \gt$

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