Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 8 - 8.3 - Vectors in the Plane - 8.3 Exercises - Page 586: 65

Answer

$ \lt 3, 0 \gt$

Work Step by Step

We are given that $||\overrightarrow{v}|| = 3$ and that: $ \theta =0^{\circ}$ We know that $v=||v|| \lt \cos \theta , \sin \theta \gt $ Thus, $v=3 \lt 1,0 \gt = \lt 3, 0 \gt$
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