Algebra and Trigonometry 10th Edition

$\overrightarrow{v} = <3, 0>$ To find the unit vector, we must first find the magnitude: $\sqrt {((3)^{2} + (0)^{2}}$ = 3 We can then write the unit vector: $\widehat{v} =$ = <1, 0> To verify that it is a unit vector, we find the magnitude: $\sqrt {((1)^{2} + (0)^{2}}$ = 1 Since the magnitude equals 1, it is a unit vector.