## Algebra and Trigonometry 10th Edition

Magnitude: $\sqrt 41$ Direction Angle: $141.34^{o}$
$\overrightarrow{v} = -5\widehat{i} + 4\widehat{j}$ Magnitude: $||\overrightarrow{v}|| = \sqrt {(-5)^{2} + 4^{2}} = \sqrt 41$ Direction Angle: $tan\theta = \frac{4}{-5} = 38.66$ Because it is in Q2, we have to subtract from 180: 180 - 38.66 = $141.34^{o}$