Answer
Magnitude: $\sqrt 41$
Direction Angle: $141.34^{o}$
Work Step by Step
$\overrightarrow{v} = -5\widehat{i} + 4\widehat{j}$
Magnitude:
$||\overrightarrow{v}|| = \sqrt {(-5)^{2} + 4^{2}} = \sqrt 41$
Direction Angle:
$tan\theta = \frac{4}{-5} = 38.66$
Because it is in Q2, we have to subtract from 180:
180 - 38.66 = $141.34^{o}$
