Answer
$ \lt \dfrac{-9}{4}, \dfrac{-15}{16} \gt $
Work Step by Step
Since $v$ has the same direction as $u$ and since it is a multiple of a unit vector $n$, we can write it as: $\overrightarrow{v} = < -12 n, -5n>$
To find the unit vector, we must first find the magnitude:
$\sqrt {((-12n)^{2} + (-5n)^{2}} = 3$
or, $144 \ n^2+25 \ n^2 =9$
This implies that $n^2=\dfrac{9}{169} \implies n=\dfrac{3}{13}$
Now, $\overrightarrow{v} = < -12 (\dfrac{3}{13}), -5 (\dfrac{3}{13})> = \lt \dfrac{-9}{4}, \dfrac{-15}{16} \gt $
